Consider the fun
ction f(x)=x^2+1 on the interval [0,4]
First lets approximate the area under the curve by using n=8 rectangles of width \Delta x=\frac{4-0}{8}=\frac{1}{2}
with using the left endpoints, midpoints and right endpoints of each subinterval.
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Notice that in this case the left endpoint Riemann sum will always be less than than the actual area
since the left hand endpoint is the minimum of the function in each subinterval.
The Riemann sum which uses the minimum point of each interval is called the Lower Sum. On the other hand the right endpoint
Riemann sum will always be greater than the actual area, which is called the Upper sum. Thus
21.5\leq A \leq 29.5
If we add more rectangles we get a far better approximation, so lets look at the Upper and Lower sums in the case of n=80 rectangles.
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With more rectangles we get a better approximation, thus we now have
The more rectangles we add the better area approximation we get.
With n=1,000 rectangles:
25.301344\leq A\leq 25.365344
With n=10,000 rectangles:
25.330133\leq A\leq25.336533
With n=1,000,000 rectangles:
25.333301\leq A\leq25.333365
Thus the actual area can be found by taking the limit of n\to\infty. This is called the defnite integral:
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