farmer r00ls

133 days ago by pablo.

var ('x') solve ([6 - 2 * ( x - 3 ) == 3 + x ], x) 
        
[x == 3]
[x == 3]
var ('x') solve ([- 5*x > 20 ], x) 
        
[[x < -4]]
[[x < -4]]
var ('x') solve([5 + x < -3], x) 
        
[[x < -8]]
[[x < -8]]
def f(x): return 3-2*x^2 f(100) 
        
-19997
-19997
var('a x') solve([a == 2 + x], x) 
        
[x == a - 2]
[x == a - 2]