first excersise

133 days ago by gonzalezalex2

solve (2*x==3 + x,x) 
        
[x == 3]
[x == 3]
solve ([-5*x>20],x) 
        
[[x < -4]]
[[x < -4]]
solve ([5+x<-3],x) 
        
[[x < -8]]
[[x < -8]]
def f(x): return 3-2*x^2 f(100) 
        
-19997
-19997
var('a') solve (a==2 + x,x) 
        
[x == a - 2]
[x == a - 2]