Lilian

133 days ago by Lilian_ili

var('x') ( [ 6 - 2 * ( x - 3 ) == 3 + x ], x) 
        
([-2*x + 12 == x + 3], x)
([-2*x + 12 == x + 3], x)
solve ([-5*x>20],x) 
        
[[x < -4]]
[[x < -4]]
solve ([5+x<-3],x) 
        
[[x < -8]]
[[x < -8]]
def f(x): return 3-2*x^2 f(100) 
        
-19997
-19997
var('a x') solve([a==2+x],x) 
        
[x == a - 2]
[x == a - 2]