Ben 3A

128 days ago by reimersb

solve (6-2*x-2*-3==3+x, x) 
        
[x == 3]
[x == 3]
solve (-5*x > 20, x) 
        
[[x < -4]]
[[x < -4]]
solve (5 + x < -3, x) 
        
[[x < -8]]
[[x < -8]]
def f(x) : return 3-2*x^2 f(100) 
        
-19997
-19997
var('A') solve (A==2+x, x) 
        
[x == A - 2]
[x == A - 2]