Untitled

127 days ago by cardonaa

solve (2*x+6,x) 
        
[x == -3]
[x == -3]
solve ([6-2*(x-3)==3+x],x) 
        
[x == 3]
[x == 3]
solve ([-5*x>20],x) 
        
[[x < -4]]
[[x < -4]]
solve ([5+x<-3],x) 
        
[[x < -8]]
[[x < -8]]
def f(x): return 3-2*x^2 f(100) 
        
-19997
-19997
var('A') solve ([A==2+x],x) 
        
[x == A - 2]
[x == A - 2]